New elementary theory of gravitation
Posted: Thu Feb 19, 2026 6:02 pm
Conversion to text from: https://meinuniversum.de/en/a2formel.html
New elementary theory of gravitation
Home page
The true nature of gravitation
First old version Second old version
I had guessed the following formula by reading about the weak interaction.
Gravitation is a kind of weak interaction (the consequence)
and is due to the subsequent reaction of the electron antineutrios with protons.
This creates a neutron and a positron - right side.
Image 1. The decisive reaction for the understanding of gravitation
(This is a diagram showing the particle reaction:
Left side: incoming proton (p) + incoming electron antineutrino (ν̄ₑ or \bar{\nu}_e)
→
Right side: neutron (n) + positron (e⁺)
It is labeled as an inelastic collision process, with an arrow or note indicating that almost all of the neutrino's momentum/impulse is transferred to the atomic nucleus/proton. The reaction is written as:
\[ p + \bar{\nu}_e \rightarrow n + e^+ \]
Particles are depicted with standard symbols, likely including charge and lepton/baryon number conservation indicators.)
Based on the reaction of Figure 1, I was able to derive the following formula no. 1.
This page (Germany) or (Poland)
explains the following gravitational formula,
(Formula no. 1 – displayed as a graphic/image on the page):
\[ F = \frac{A}{r^2} \, \sigma \, I_n \, N_1 \, N_2 \]
and where I got the numbers from and much more.
The most important thing is that the neutrino's almost all impulse is dedicated to the atomic nucleus.
It is also an inelastic collision!
Formula no. 1.
The variables are only explained below for gravitation.
F - gravity in [N] (Newtons)
σ - cross section for the reaction from image 1
Iₙ - electron antineutrinos energy density or pressure
N₁ - the total number of nucleons in the first body
N₂ - the total number of nucleons in the second body
A = 1 m²
σ = 6.3 10⁻⁴⁸ m²
Iₙ = 2.921213972 10⁻¹⁷ N/m²
N₁ = M₁ / u
N₂ = M₂ / u
u = 1.6605390666 10²⁷ kg (According to the CODATA table from 2018)
One can find strong experimental confirmation of neutrino flux on gravitational field in the following works.
Beginning, new knowledge 10/04/2023
"Gravitational anomaly in the proximity of nuclear reactors" and link to the work Vixra and still local on my website.
"Detection of solar neutrinos with a torsion balance with sapphire crystal" on the IOP side
or at local link to the work.
End, new knowledge
The following theory from Le Sage would fit in very well,
if you replaced the Le Sages "ultramundane bodies" with antineutrinos.
Force pressure model for gravitation
We are in a sea of neutrinos, e.g. should have a temperature of 1.945 ° K in background radiation
and its impulse is completely transmitted in the reaction to matter shown above.
(The temperature corresponds to the energy density (pressure) of approx. 1.08 10⁻¹⁴ J/m³ (N/m²)
only for neutrinos, which you can read on the following website.
https://en.wikipedia.org/wiki/Cosmic_ne ... background
A calculation of energy density of electron antineutrinos that come from Big Bang and have energy greater than 1.8 MeV,
would confirm my model of gravity,
if the calculations gave the value of approx. 3 10⁻¹⁷ N / m².
----------------------------------------------------------------------------------------------------
Miroslaw Wilczak
New elementary theory of gravitation
Home page
The true nature of gravitation
First old version Second old version
I had guessed the following formula by reading about the weak interaction.
Gravitation is a kind of weak interaction (the consequence)
and is due to the subsequent reaction of the electron antineutrios with protons.
This creates a neutron and a positron - right side.
Image 1. The decisive reaction for the understanding of gravitation
(This is a diagram showing the particle reaction:
Left side: incoming proton (p) + incoming electron antineutrino (ν̄ₑ or \bar{\nu}_e)
→
Right side: neutron (n) + positron (e⁺)
It is labeled as an inelastic collision process, with an arrow or note indicating that almost all of the neutrino's momentum/impulse is transferred to the atomic nucleus/proton. The reaction is written as:
\[ p + \bar{\nu}_e \rightarrow n + e^+ \]
Particles are depicted with standard symbols, likely including charge and lepton/baryon number conservation indicators.)
Based on the reaction of Figure 1, I was able to derive the following formula no. 1.
This page (Germany) or (Poland)
explains the following gravitational formula,
(Formula no. 1 – displayed as a graphic/image on the page):
\[ F = \frac{A}{r^2} \, \sigma \, I_n \, N_1 \, N_2 \]
and where I got the numbers from and much more.
The most important thing is that the neutrino's almost all impulse is dedicated to the atomic nucleus.
It is also an inelastic collision!
Formula no. 1.
The variables are only explained below for gravitation.
F - gravity in [N] (Newtons)
σ - cross section for the reaction from image 1
Iₙ - electron antineutrinos energy density or pressure
N₁ - the total number of nucleons in the first body
N₂ - the total number of nucleons in the second body
A = 1 m²
σ = 6.3 10⁻⁴⁸ m²
Iₙ = 2.921213972 10⁻¹⁷ N/m²
N₁ = M₁ / u
N₂ = M₂ / u
u = 1.6605390666 10²⁷ kg (According to the CODATA table from 2018)
One can find strong experimental confirmation of neutrino flux on gravitational field in the following works.
Beginning, new knowledge 10/04/2023
"Gravitational anomaly in the proximity of nuclear reactors" and link to the work Vixra and still local on my website.
"Detection of solar neutrinos with a torsion balance with sapphire crystal" on the IOP side
or at local link to the work.
End, new knowledge
The following theory from Le Sage would fit in very well,
if you replaced the Le Sages "ultramundane bodies" with antineutrinos.
Force pressure model for gravitation
We are in a sea of neutrinos, e.g. should have a temperature of 1.945 ° K in background radiation
and its impulse is completely transmitted in the reaction to matter shown above.
(The temperature corresponds to the energy density (pressure) of approx. 1.08 10⁻¹⁴ J/m³ (N/m²)
only for neutrinos, which you can read on the following website.
https://en.wikipedia.org/wiki/Cosmic_ne ... background
A calculation of energy density of electron antineutrinos that come from Big Bang and have energy greater than 1.8 MeV,
would confirm my model of gravity,
if the calculations gave the value of approx. 3 10⁻¹⁷ N / m².
----------------------------------------------------------------------------------------------------
Miroslaw Wilczak